How do you solve $(x – 2) ² = 4(4 – x)$ ?

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Answer 1 · 2016-03-27T10:27:32

$x=-2sqrt3$ or $x=2sqrt3$

Simplifying $(x-2)^2=4(4-x)$ , we get

$x^2-4x+4=16-4x$ or

$x^2-4x+4x+4-16=0$ or

$x^2-12=0$ or

$(x+sqrt12)(x-sqrt12)=0$ or

$x=-sqrt12=-2sqrt3$ or $x=2sqrt3$

How do you solve (x – 2) ² = 4(4 – x)(x – 2) ² = 4(4 – x)?