How do you solve $x^{2} + 4 x = 0$ $x^2 + 4x = 0$ ?

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Answer 1 · 2016-03-28T16:50:25

The solutions are :
$x = 0$ $color(blue)( x=0$
$x = - 4$ $color(blue)(x=-4$

$x^{2} + 4 x = 0$ $x^2 + 4x = 0$

$x$ $x$ is common to both terms.
$x \cdot (x + 4) = 0$ $color(blue)(x ) * ( x +4 ) = 0$

Equating each of the factors to $0$ $0$ will provide the solutions.

How do you solve x^2 + 4x = 0x2+4x=0x^2 + 4x = 0?