How do you solve $x^{2} - 4 x = 0$ $x^2-4x=0$ ?

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Answer 1 · 2016-04-11T08:05:59

$x = 0$ $x=0$ or 4

If we take $x$ $x$ out as a common factor, we get:

$x (x - 4) = 0$ $x(x-4)=0$

Using the null factor law we can now solve for $x$ $x$ (essentially determining the values required to make each value of $x = 0$ $x=0$ ):

$x = 0$ $x=0$
or $x = 4$ $x=4$ .

How do you solve x2−4x=0x^2-4x=0 ?