Question

How do you solve `x^2+4x+2=0` by factoring?

Answer 1

`x^2+4x+2 = (x+2+sqrt(2))*(x+2-sqrt(2))`
therefore `x^2+4x+2=0`
`rarr x=-2-sqrt(2) " or " x=-2+sqrt(2)`

Explanation:

Honestly, it is unlikely that most people would recognize the given factors. This is one situation where you would be better served by using the quadratic formula for roots.
`color(white)("XXXX")x=(-b+-sqrt(b^2-4ac))/(2a)`