How do you solve x^2+4x - 32=0x2+4x−32=0?

1 Answer
Jim G.
Mar 29, 2018

x=-8" or "x=4x=−8 or x=4

Explanation:

"the factors of - 32 which sum to + 4 are + 8 and - 4"the factors of - 32 which sum to + 4 are + 8 and - 4

rArr(x+8)(x-4)=0⇒(x+8)(x−4)=0

"equate each factor to zero and solve for x"equate each factor to zero and solve for x

x+8=0rArrx=-8x+8=0⇒x=−8

x-4=0rArrx=4x−4=0⇒x=4

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