Question

How do you solve `x^2-4x=6` algebraically?

Answer 1

`x = 4 +- sqrt10`

Explanation:

`y = x^2 - 4x - 6 = 0`
Use the improved quadratic formula (Socratic , Google Search).
`D = d^2 = b^2 - 4ac = 16 + 24 = 40` --> `d = +- 2sqrt10`
There are 2 real roots:
`x = -b/(2a) +- d/(2a) = 8/2 +- (2sqrt10)/2 = 4 +- sqrt10`