How do you solve x^2<=4x using a sign chart?

1 Answer
Nov 16, 2016

Move every term to one side, factor the expression, and determine when each factor is+or-. Multiply these+and-intervals from the factors to get the+and-intervals for the product (and thus the original inequality).

Explanation:

x^2<=4x
x^2-4x<=0 Move everything to one side
x(x-4)<=0 Factor the expression

This is now written as the product of two factors, x and x-4. The values of x that make the factors 0 are the "points of interest", because it is only at these points where the value of x^2-4x could change from being<=0 to not being<=0. We set each factor equal to 0 and solve for x:

x=0 or x-4=0
=>x=0 or x=4

So we have three intervals to examine: below 0, between 0 and 4, and above 4.

A sign chart can be made like this:
. . . . . . . . . .---------0----------4-----------
x
x-4
. . . . . . . . . .----------------------------------
x(x-4)

Fill in the sign chart with + and - signs to reflect where each factor is<=0. For example: the factor x-4 is negative when x<4; it's 0 when x=4; and it's positive when x>4.

. . . . . . . . . .---------0---------4-----------
x . . . . . . . . -- 0+++++
x-4. . . . . ---- 0+++
. . . . . . . . . .----------------------------------
x(x-4)

To complete the bottom row of the sign chart, each interval is filled with the product of all the signs above it. For example, when x<0, (-) x (-) = (+).

. . . . . . . . . .---------0--------4-----------
x . . . . . . . . -- 0+++++
x-4 . . . . ---- 0+++
. . . . . . . . . .----------------------------------
x(x-4) . ++0--0+++

This tells you that x(x-4) (in other words, x^2-4x) will be negative only when x is between 0 and 4, and it will be 0 at those endpoints, i.e. x^2-4x<=0 when 0<=x<=4. And since x^2-4x<=0 is equivalent to our original inequality x^2<=4x, we are done.

The solution is 0<=x<=4.
Or x in [0,4] if you prefer interval notation.

Go ahead and try some values for yourself: say x=3. We should expect the inequality to be true. Well, is it?

x^2<=4x
<=>3^2<=4(3) (when x=3)
<=>9<=12
Which is true!