How do you solve #x+2/5=-3/2# by clearing the fractions?

1 Answer
May 2, 2017

#color(green)(x=-19/10)#
#color(white)("XXX")#see below for solution method by "clearing the fractions"

Explanation:

Given
#color(white)("XXX")color(blue)(x+2/5)=color(blue)(-3/2)#

We can clear the fractions by multiplying both sides by the #color(red)(LCM)# (Least Common Multiple) of all denominators appearing in the equation.

The denominators that we have in the given equation are #color(blue)2# and #color(blue)5#;
their color(red)(LCM) is #color(red)(10)#;
so we will multiply both sides by #color(red)(10)#

#color(white)("XXX")color(red)(10)xx(color(blue)(x+2/5))=color(red)(10)xx(color(blue)(-3/2))#

Simplifying
#color(white)("XXX")10x+4=-15#

#color(white)("XXX")10x=-19#

#color(white)("XXX")x=-19/10#