How do you solve $x^2 + 5 = 41$ ?

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Answer 1 · 2018-05-13T05:45:00

$x=6$

$x^2+5=41$

$x^2=36$

$pm6^2=36$

$x=pm6$

hope this helps

Answer 2 · 2018-05-13T06:50:36

$x=pm6$

$x^2+5=41$

$x^2+5color(red)(-5)=41color(red)(-5)$

$x^2=36$

$sqrt(x^2)=sqrt36$

$x=pm6$

We can graph both the right and left hand sides:

graph{(y-x^2-5)(y-0x-41)=0 [-11.31, 12.99, 32.25, 44.41]}

How do you solve x^2 + 5 = 41x^2 + 5 = 41?