How do you solve $x^{2} + 5 x = 0$ $x^2 + 5x = 0$ ?

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How do you solve $x^{2} + 5 x = 0$ $x^2 + 5x = 0$ ?

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Answer 1 · 2018-04-21T06:43:11

$x_{1} = 0$ $x_1 = 0$
$x_{2} = - 5$ $x_2 = -5$

Explanation:

$x^{2} + 5 x = 0$ $x^2 + 5x = 0$
$x (x + 5) = 0$ $x(x+5) = 0$

By the null factor law either $x$ $x$ or $x + 5$ $x+5$ must be equal to $0$ $0$ .

$x_{1} = 0$ $x_1 = 0$
$x_{2} = - 5$ $x_2 = -5$

Answer 2 · 2018-04-21T07:59:16

$x = - 5 or x = 0$ $x=-5" or "x=0$

Explanation:

$take out a common factor x$ $"take out a "color(blue)"common factor "x$

$\Rightarrow x (x + 5) = 0$ $rArrx(x+5)=0$

$equate each of the factors to zero and solve for x$ $"equate each of the factors to zero and solve for x"$

$\Rightarrow x = 0$ $rArrx=0$

$x + 5 = 0 \Rightarrow x = - 5$ $x+5=0rArrx=-5$

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How do you solve $x^{2} + 5 x = 0$ $x^2 + 5x = 0$ ?

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How do you solve x^2 + 5x = 0x2+5x=0x^2 + 5x = 0?

2 Answers

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How do you solve $x^{2} + 5 x = 0$ $x^2 + 5x = 0$ ?