How do you solve $x^{2} + 5 x = 0$ $x^2+5x=0$ ?

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Answer 1 · 2016-04-17T17:41:45

The solutions are:
$x = 0$ $color(blue)(x = 0$
$x = - 5$ $color(blue)(x= - 5$

$x^{2} + 5 x = 0$ $x^2 + 5x = 0$

$x$ $x$ is common to both terms of the expression.

$x (x + 5) = 0$ $x ( x + 5) = 0$

Equating the factors to zero to obtain the solutions:

$x = 0$ $color(blue)(x = 0$

$x + 5 = 0$ $x+5= 0$
$x = - 5$ $color(blue)(x= - 5$

How do you solve x2+5x=0x^2+5x=0?