How do you solve $x^{2} - 5 x = 0$ $x^2 - 5x = 0$ by completing the square?

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Answer 1 · 2018-06-06T07:05:50

${(x - 2.5)}^{2} - 6.25 = 0$ $(x-2.5)^2-6.25=0$

${(x - 2.5)}^{2} = 6.25$ $(x-2.5)^2=6.25$

$x - 2.5 = \pm \sqrt{6.25}$ $x-2.5=pmsqrt6.25$

$x = 2.5 + 2.5 or x = 2.5 - 2.5$ $x=2.5+2.5 or x=2.5-2.5$

$x = 5 or x = 0$ $x=5 or x=0$

How do you solve x^2 - 5x = 0x2−5x=0 x^2 - 5x = 0 by completing the square?