How do you solve $x^2 = 5x +2$ ?

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Answer 1 · 2016-07-19T13:45:34

$x=(10+sqrt(33))/2, (10 -sqrt(33))/2$

$x^2-5x-2=0$

then use the qudratic formula enter image source here

$x=5+-sqrt(5^2-(4*1*-2))/(2*1)$
$x=5+-sqrt(33)/(2)$
$x=(10+sqrt(33))/2, (10 -sqrt(33))/2$

How do you solve x^2 = 5x +2x^2 = 5x +2?