How do you solve $x^2 + 5x + 3 = 0$ ?

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Answer 1 · 2015-08-02T06:13:27

The solutions are
$color(blue)(x=(-5+sqrt(13))/2 , x=(-5-sqrt(13))/2$

The equation $x^2+5x+3$ is of the form $color(blue)(ax^2+bx+c=0$ where:
$a=1, b=5, c=3$

The Discriminant is given by:
$Delta=b^2-4*a*c$

$= (5)^2-(4*(1)*3)$

$= 25-12=13$

As $Delta>0$ there are two solutions,
The solutions are found using the formula
$x=(-b+-sqrtDelta)/(2*a)$

$x = (-(5)+-sqrt(13))/(2*1) =color(blue)( (-5+sqrt(13))/2$

$x = color(blue)((-5-sqrt(13))/2$

How do you solve x^2 + 5x + 3 = 0x^2 + 5x + 3 = 0?