How do you solve $x^{2} - 5 x - 6 = 0$ $x^2-5x-6=0$ ?

Question

1393 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2016-04-30T06:21:24

$x = - 1, 6$ $x=color(red)(-1), color(blue)6$

$x^{2} - 5 x - 6 = 0$ $x^2-5x-6=0$

Find two numbers that when added equal $- 5$ $-5$ and when multiplied equal $- 6$ $-6$ . The numbers $- 6$ $-6$ and $1$ $1$ meet the criteria.

Rewrite the equation in factored form.

$(x + 1) (x - 6) = 0$ $(x+1)(x-6)=0$

Set each factor equal to zero and solve for $x$ $x$ .

$(x + 1) = 0$ $color(red)((x+1)=0$

$x = - 1$ $color(red)(x=-1$

$(x - 6) = 0$ $color(blue)((x-6)=0)$

$x = 6$ $color(red)(x=6$

$x = - 1, 6$ $x=color(red)(-1), color(blue)6$

How do you solve x2−5x−6=0 x^2-5x-6=0?