How do you solve $x^2 - 5x - 6 = 0$ ?

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Answer 1 · 2016-03-20T16:48:03

The solutions are:
$x=6$
$x=-1$

$x^2 - 5x - 6 = 0$

The equation is of the form $color(blue)(ax^2+bx+c=0$ where:
$a=1, b=-5, c=-6$

The Discriminant is given by:

$Delta=b^2-4*a*c$

$= (-5)^2-(4* 1 * ( -6) )$

$= 25 + 24 = 4 9$

The solutions are normally found using the formula
$x=(-b+-sqrtDelta)/(2*a)$

$x = (-(-5)+-sqrt(49))/(2*1) = ((5+-7))/ 2$

$x=((5+ 7))/ 2 = 12/2 = 6$

$x=((5- 7))/ 2 = -2/2 = -1$

How do you solve x^2 - 5x - 6 = 0x^2 - 5x - 6 = 0?