How do you solve $x^2-5x+6=0$ ?

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Answer 1 · 2016-04-19T05:44:41

The solutions are
$color(blue)( x= 3$

$color(blue)( x = 2$

$x^2 - 5x + 6 = 0$

The equation is of the form $color(blue)(ax^2+bx+c=0$ where:
$a=1, b=-5, c= 6$

The Discriminant is given by:

$Delta=b^2-4*a*c$

$= (-5)^2-(4* 1 * 6)$

$= 25 - 24 = 1$

The solutions are normally found using the formula
$x=(-b+-sqrtDelta)/(2*a)$

$x = (-(-5)+-sqrt(1))/(2*1) = (5 +- 1 )/2$

$color(blue)( x = ( 5 +1)/2 = 6/2 = 3$

$color(blue)( x = ( 5 -1)/2 = 4 /2 = 2$

How do you solve x^2-5x+6=0 x^2-5x+6=0 ?