How do you solve $x^2-5x+6=0$ by factoring?

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Answer 1 · 2015-08-06T11:40:24

Since the $6$ has a $+$ -sign you're looking for two factors of $6$ that add up to $-5$

These can only be $-2and-3$ so the factoring goes:
$(x-2)(x-3)=0->x=2orx=3$

How do you solve x^2-5x+6=0 x^2-5x+6=0 by factoring?