How do you solve $x^2 + 5x - 8 = 4x + 4$ ?

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Answer 1 · 2016-04-01T02:31:06

x= 3, x = -4

$y = x^2 + x - 12 = 0$
Find 2 numbers knowing sum (-1 = -b) and product (c = -12). They are the factor pair (3, -4). The 2 real roots are: 3 and -4.

How do you solve x^2 + 5x - 8 = 4x + 4x^2 + 5x - 8 = 4x + 4?