How do you solve $x^{2} + 6 = - 5 x$ $x^2 + 6 = -5x$ ?

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Answer 1 · 2018-03-28T21:24:10

The 2 solutions are $x = - 2 and x = - 3$ $x = -2 and x = -3$ .

Get everything on one side of the equal sign.

$x^{2} + 5 x + 6 = 0$ $x^2 +5x +6 = 0$

Now factor.

$(x + 2) \cdot (x + 3) = 0$ $(x + 2)*(x+3) = 0$

The left side will equal zero when either of the 2 factors equal zero. so the 2 solutions are found as follows:

$x + 2 = 0 therefore x = - 2$ $x + 2 = 0 " therefore " x = -2$

$x + 3 = 0 therefore x = - 3$ $x + 3 = 0 " therefore " x = -3$

I hope this helps,
Steve

How do you solve x^2 + 6 = -5xx2+6=−5xx^2 + 6 = -5x?