How do you solve $x^2 + 6x = 1$ ?

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Answer 1 · 2018-03-09T06:14:55

$x=-3+-sqrt10$
$x approx 0.16228 or approx-6.16228$

$x^2+6x=1$

$x^2+6x-1=0$

$x= (-6+-sqrt(6^2-4xx1xx(-1)))/(2xx1)$

$= -3+-sqrt40/2$

$= -3 +-sqrt(2xx2xx2xx5)/2$

$=-3+- (2sqrt10)/2$

$=-3+-sqrt10$

$x=-3+-sqrt10$

$x approx 0.16228 or approx-6.16228$

How do you solve x^2 + 6x = 1x^2 + 6x = 1?