How do you solve $x^2=6x-12$ ?

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Answer 1 · 2016-06-28T14:08:57

$x=3+-sqrt3 i$

let's rewrite the equation in the general form:

$x^2-6x+12=0$

and solve by the quadratic formula used when b is even and a=1

$x=(-b/2+-sqrt((b/2)^2-c))$

In this case a=1; b=-6; c=12, so

$x=3+-sqrt(9-12)$

$x=3+-sqrt3 i$

no real solution, but complex

How do you solve x^2=6x-12x^2=6x-12?