How do you solve $x^2 - 6x +8 = 0$ ?

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Answer 1 · 2018-03-24T04:14:28

The zeroes are 2 and 4

$x^2$ - 6x + 8 = 0
$x^2$ - 4x -2x + 8 = 0
x(x - 4) - 2(x - 4) = 0
(x - 2)(x - 4) = 0
x - 2 = 0 or x - 4 = 0
x = 2 or x = 4

Answer 2 · 2018-03-24T04:17:06

$x=2,4$

Solve:

$x^2-6x+8=0$

Factor.

$(x-2)(x-4)=0$

Solve for $x$ .

$x-2=0$

$x=2$

$x-4=0$

$x=4$

$x=2,4$

graph{y=x^2-6x+8 [-10, 10, -5, 5]}

How do you solve x^2 - 6x +8 = 0 x^2 - 6x +8 = 0 ?