How do you solve $x^{2} - 6 x + 9 = 0$ $x^2 - 6x + 9 = 0$ graphically and algebraically?

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How do you solve $x^{2} - 6 x + 9 = 0$ $x^2 - 6x + 9 = 0$ graphically and algebraically?

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Answer 1 · 2017-09-02T04:31:19

$x = 3$ $x=3$

Explanation:

Given -

$x^{2} - 6 x + 9 = 0$ $x^2-6x+9=0$

$x^{2} - 3 x - 3 x + 9 = 0$ $x^2-3x-3x+9=0$

$x (x - 3) - 3 (x - 3) = 0$ $x(x-3)-3(x-3)=0$

$(x - 3) (x - 3) = 0$ $(x-3)(x-3)=0$

$x = 3$ $x=3$

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How do you solve $x^{2} - 6 x + 9 = 0$ $x^2 - 6x + 9 = 0$ graphically and algebraically?

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How do you solve x2−6x+9=0x^2 - 6x + 9 = 0 graphically and algebraically?

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How do you solve $x^{2} - 6 x + 9 = 0$ $x^2 - 6x + 9 = 0$ graphically and algebraically?