How do you solve $x^2+ 7x = - 10$ ?

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Answer 1 · 2016-05-09T15:21:01

The solutions are:

$x = -2$

$x= - 5$

$x^2 + 7x = -10$

$x^2 + 7x + 10 =0$

The equation is of the form $color(blue)(ax^2+bx+c=0$ where:

$a=1, b=7, c=10$

The Discriminant is given by:

$Delta=b^2-4*a*c$

$= (7)^2-(4* 1 * 10)$

$= 49 - 40 = 9$

The solutions are normally found using the formula
$x=(-b+-sqrtDelta)/(2*a)$

$x = ((-7)+-sqrt(9))/(2*1) = ((-7+-sqrt9))/2$

$x = (-7+- 3)/2$

$x= ( - 7 + 3) / 2 = -4/2 = -2$

$x= ( - 7 - 3) / 2 = -10 / 2 = - 5$

How do you solve x^2+ 7x = - 10x^2+ 7x = - 10?