How do you solve #x^ { 2} + 7x + 12= 6#?
1 Answer
Jun 16, 2018
Explanation:
#"arrange the equation in "color(blue)"standard form"#
#•color(white)(x)ax^2+bx+c=0#
#"subtract 6 from both sides"#
#x^2+7x+6=0#
#"the factors of + 6 which sum to + 7 are + 6 and + 1"#
#(x+6)(x+1)=0#
#"equate each factor to zero and solve for "x#
#x+6=0rArrx=-6#
#x+1=0rArrx=-1#
