Question

How do you solve `x^ { 2} + 7x + 12= 6`?

Answer 1

`x=-6" or "x=-1`

Explanation:

`"arrange the equation in "color(blue)"standard form"`

`•color(white)(x)ax^2+bx+c=0`

`"subtract 6 from both sides"`

`x^2+7x+6=0`

`"the factors of + 6 which sum to + 7 are + 6 and + 1"`

`(x+6)(x+1)=0`

`"equate each factor to zero and solve for "x`

`x+6=0rArrx=-6`

`x+1=0rArrx=-1`