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How do you solve $x^{2} + 8 = 28$ $x^2 + 8 = 28$ ?

1 Answer

Jul 20, 2015

$x = \pm 2 \sqrt{5}$ $color(green)(x=+-2sqrt5$

Explanation:

$x^{2} + 8 = 28$ $x^2+8=28$
$x^{2} = 28 - 8$ $x^2=28-8$

$x^{2} = 20$ $x^2=20$
$x = \pm \sqrt{20}$ $x=+-sqrt20$

$x = \pm 2 \sqrt{5}$ $color(green)(x=+-2sqrt5$

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