How do you solve $x^2-8=8$ by factoring?

Question

1605 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2015-08-20T13:03:21

The solutions are
$color(blue)(x=-4$
$color(blue)(x=4$

$x^2−8=8$

$x^2−8-8=0$

$x^2−16=0$

$x^2−4^2=0$

By property
$color(blue)(a^2-b^2=(a+b)(a-b)$

Applying the same:
$x^2−4^2=(x+4)(x-4)$
$(x+4)(x-4)$ is the factorised form of the expression.
Now we equate these factors to the R.H.S.

$x+4=0, color(blue)(x=-4$
$x-4=0, color(blue)(x=4$

How do you solve x^2-8=8x^2-8=8 by factoring?