How do you solve $x^{2} + 8 x = 0$ $x^2 + 8x = 0$ ?

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How do you solve $x^{2} + 8 x = 0$ $x^2 + 8x = 0$ ?

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Answer 1 · 2016-06-08T14:54:50

$x = - 8, 0$ $x=-8,0$

Explanation:

Factor an $x$ $x$ term from both terms on the left-hand side.

$x (x + 8) = 0$ $x(x+8)=0$

Now that we have two separate terms being multiplied and equaling $0$ $0$ , the terms being $x$ $x$ and $(x + 8)$ $(x+8)$ , we know that either one of these terms must be equal to $0$ $0$ .

So, we have $x = 0$ $x=0$ or $x + 8 = 0$ $x+8=0$ , so the two solutions are $x = - 8, 0$ $x=-8,0$ .

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How do you solve $x^{2} + 8 x = 0$ $x^2 + 8x = 0$ ?

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