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How do you solve $x^{2} - 8 x = - 16$ $x^2 - 8x = -16$ ?

1 Answer

May 27, 2016

x has equal roots : $x = 4$ $x=4$

Explanation:

$x^2-8x+16=0 or (x-4)^2 =0 or (x-4)(x-4)=0 :. x=4 and x=4$ [Ans]

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