How do you solve $x^{2} - 8 x - 20 = 0$ $x^2 - 8x - 20 = 0$ ?

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How do you solve $x^{2} - 8 x - 20 = 0$ $x^2 - 8x - 20 = 0$ ?

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Answer 1 · 2016-02-17T21:15:09

x = 10 , x = - 2

Explanation:

first factor the quadratic by considering the factors of - 20 which sum to - 8.
These are - 10 and +2

$\Rightarrow x^{2} - 8 x - 20 = (x - 10) (x + 2) = 0$ $rArr x^2 - 8x - 20 = (x - 10 )(x + 2 ) = 0$

hence (x - 10 ) = 0 $\Rightarrow x = 10 or (x + 2) = 0 \Rightarrow x = - 2$ $rArr x = 10 " or " (x + 2 ) = 0 rArr x = - 2$

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How do you solve $x^{2} - 8 x - 20 = 0$ $x^2 - 8x - 20 = 0$ ?

1 Answer

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How do you solve x2−8x−20=0x^2 - 8x - 20 = 0?

1 Answer

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How do you solve $x^{2} - 8 x - 20 = 0$ $x^2 - 8x - 20 = 0$ ?