How do you solve $x^{2} - 9 x = 0$ $x^2-9x=0$ ?

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Answer 1 · 2016-03-25T15:54:14

$x = 0 or 9$ $x = 0 or 9$

In order to solve $x^{2} - 9 x = 0$ $x^2 -9x = 0$
begin by factoring out an $x$ $x$ .

$x (x - 9) = 0$ $x(x-9)=0$
now set each term equal to zero and solve for $x$ $x$

$x = 0$ $x=0$

$x - 9 = 0$ $x-9=0$ a
$xcancel(-9)cancel(+9) = 0+9$
$x=9$

$x = 0 or 9$

How do you solve x^2-9x=0x2−9x=0x^2-9x=0?