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How do you solve $x^{2} - 9 x = - 8$ $x^2 - 9x = -8$ ?

1 Answer

Feb 5, 2016

$x = 8$ $x=8$ or $x = 1$ $x=1$

Explanation:

Given:
$XXX x^{2} - 9 x = - 8$ $color(white)("XXX")x^2-9x=-8$

Re-write as
$XXX x^{2} - 9 x + 8 = 0$ $color(white)("XXX")x^2-9x+8=0$

Factor
$XXX (x - 8) (x - 1) = 0$ $color(white)("XXX")(x-8)(x-1)=0$

Which implies either $(x - 8) = 0$ $(x-8)=0$ or $(x - 1) = 0$ $(x-1)=0$

So either $x = 8$ $x=8$ or $x = 1$ $x=1$

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