How do you solve x^2=-9x-8? Algebra Quadratic Equations and Functions Comparing Methods for Solving Quadratics 1 Answer Hgsfjc S. Apr 9, 2018 x= -1 or-8 Explanation: First use null factor law to put the -x^2 on the other side hence making 0= -x^2 -9x-8. Simplify by dividing by-1 = x^2 +9x+8=0. Then use cross method to factorise which becomes (x+8)(x+1)=0 the x being -8 or -1 as the answer Answer link Related questions What are the different methods for solving quadratic equations? What would be the best method to solve -3x^2+12x+1=0? How do you solve -4x^2+4x=9? What are the two numbers if the product of two consecutive integers is 72? Which method do you use to solve the quadratic equation 81x^2+1=0? How do you solve -4x^2+4000x=0? How do you solve for x in x^2-6x+4=0? How do you solve x^2-6x-16=0 by factoring? How do you solve by factoring and using the principle of zero products x^2 + 7x + 6 = 0? How do you solve x^2=2x? See all questions in Comparing Methods for Solving Quadratics Impact of this question 2535 views around the world You can reuse this answer Creative Commons License