How do you solve $x^2-x= -1$ ?

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Answer 1 · 2015-07-28T19:28:36

$x=1/2+-isqrt(3)/2$

Complete the square:
$x^2-x=(x-1/2)^2-1/4=-1$

Rearrange to make $x$ the subject:
$(x-1/2)^2-1/4=-1$

=>

$(x-1/2)^2=-3/4$

=>

$x-1/2=+-isqrt(3)/2$

=>

$x=1/2+-isqrt(3)/2$

How do you solve x^2-x= -1 x^2-x= -1?