How do you solve $x^{2} + x + 1 = 0$ $x^2+x+1=0$ ?

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Answer 1 · 2018-03-24T20:11:24

x = $\frac{- 1 \pm i \sqrt{3}}{2}$ $(-1 ± isqrt(3))/2$

Use the quadratic formula :
x = $\frac{- b \pm \sqrt{b^{2} - 4 a c}}{2 a}$ $(-b ± sqrt(b^2 - 4ac))/(2a)$

x = $\frac{- 1 \pm \sqrt{1 - 4 (1) (1)}}{2 (1)}$ $(-1 ± sqrt(1 - 4(1)(1)))/(2(1))$

x = $\frac{- 1 \pm \sqrt{- 3}}{2}$ $(-1 ± sqrt(-3))/2$

x = $\frac{- 1 \pm i \sqrt{3}}{2}$ $(-1 ± isqrt(3))/2$

How do you solve x2+x+1=0x^2+x+1=0?