How do you solve $x^2 - x + 2 = 0$ ?

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Answer 1 · 2015-10-10T06:22:53

The solutions are
$color(blue)(x= (1+sqrt(-7))/2$

$color(blue)(x= (1-sqrt(-7))/2$

$x^2-x+2$

The equation is of the form $color(blue)(ax^2+bx+c=0$ where:
$a=1, b=-1, c=2$

The Discriminant is given by:
$Delta=b^2-4*a*c$
$= (-1)^2-(4*1*2)$
$= 1-8=-7$

The solutions are found using the formula
$x=(-b+-sqrtDelta)/(2*a)$

$x = (-(-1)+-sqrt(-7))/(2*1) = (1+-sqrt(-7))/2$

The solutions are
$color(blue)(x= (1+sqrt(-7))/2$
$color(blue)(x= (1-sqrt(-7))/2$

How do you solve x^2 - x + 2 = 0x^2 - x + 2 = 0?