How do you solve (x+2)(x-4)=12(x+2)(x−4)=12?
1 Answer
Oct 11, 2017
See the answer below...
Explanation:
(x+2)(x-4)=12(x+2)(x−4)=12
=>x^2-2x-8=12⇒x2−2x−8=12
=>x^2-2x-20=0⇒x2−2x−20=0 Now apply Pythagoras rule,
The answt is following....
Hope it helps...
Thank you...
