How do you solve #(x+2)(x-4)=12#?
1 Answer
Oct 11, 2017
See the answer below...
Explanation:
#(x+2)(x-4)=12#
#=>x^2-2x-8=12#
#=>x^2-2x-20=0# Now apply Pythagoras rule,
The answt is following....
Hope it helps...
Thank you...
