How do you solve $- x^{2} - x + 6 < 0$ $-x^2 - x + 6 < 0$ ?

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Answer 1 · 2015-05-04T02:03:21

The given quadratic inequality is same as $x^{2} + x - 6 > 0$ $x^2+x-6>0$ . Factorise it (x+3)(x-2)>0

It has two solutions, x+3>0 and x-2>0, Or x+3<0 and x-2<0.

In the first case x>-3 and x>2 which means x>2. If x>2, it would automatically mean x>-3

Like wise in the second case, it would mean x<-3. On the number line the inequality would be represented by x>2 and x<-3

How do you solve −x2−x+6<0-x^2 - x + 6 < 0?