How do you solve $x^{2} - x - 6 = 0$ $x^2 - x - 6 = 0$ ?

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How do you solve $x^{2} - x - 6 = 0$ $x^2 - x - 6 = 0$ ?

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Answer 1 · 2018-06-13T17:37:23

$x = - 2 or x = 3$ $x=-2" or "x=3$

Explanation:

$the factors of - 6 which sum to - 1 are - 3 and + 2$ $"the factors of - 6 which sum to - 1 are - 3 and + 2"$

$(x - 3) (x + 2) = 0$ $(x-3)(x+2)=0$

$equate each factor to zero and solve for x$ $"equate each factor to zero and solve for "x$

$x + 2 = 0 \Rightarrow x = - 2$ $x+2=0rArrx=-2$

$x - 3 = 0 \Rightarrow x = 3$ $x-3=0rArrx=3$

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How do you solve $x^{2} - x - 6 = 0$ $x^2 - x - 6 = 0$ ?

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How do you solve x^2 - x - 6 = 0x2−x−6=0x^2 - x - 6 = 0?

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How do you solve $x^{2} - x - 6 = 0$ $x^2 - x - 6 = 0$ ?