How do you solve ${(x - 3)}^{2} = 36$ $(x-3)^2=36$ ?

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How do you solve ${(x - 3)}^{2} = 36$ $(x-3)^2=36$ ?

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Answer 1 · 2015-10-31T15:51:46

$x = 9 and x = - 3$ $x=9 and x=-3$

Explanation:

${(x - 3)}^{2} = 36$ $(x-3)^2 = 36$

${(x - 3)}^{2} = 6^{2}$ $(x-3)^2 = 6^2$

$\sqrt{{(x - 3)}^{2}}$ $sqrt ((x-3)^2)$ = 6

$\pm (x - 3)$ $+- (x-3)$ = 6

either,
taking +,
$+ (x - 3) = 6$ $+ (x-3) =6$
$x - 3 = 6$ $x-3=6$
$x = 6 + 3$ $x=6+3$
So,
$x = 9$ $x=9$

Or,
Taking -,
$- (x - 3) = 6$ $-(x-3) =6$
$- x + 3 = 6$ $-x +3 =6$
$- x = 6 - 3$ $-x = 6-3$
$- x = 3$ $-x= 3$
So,
$x = - 3$ $x= -3$

Answer 2 · 2015-10-31T15:54:09

I found:
$x_{1} = 9$ $x_1=9$
$x_{2} = - 3$ $x_2=-3$

Explanation:

You can take the square root of both sides and get:
$(x - 3) = \pm \sqrt{36}$ $(x-3)=+-sqrt(36)$
$x = 3 \pm 6$ $x=3+-6$
so you have two possibilities:
$x_{1} = 3 + 6 = 9$ $x_1=3+6=9$
$x_{2} = 3 - 6 = - 3$ $x_2=3-6=-3$
Both work when inserted into your original equation.

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How do you solve ${(x - 3)}^{2} = 36$ $(x-3)^2=36$ ?

2 Answers

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How do you solve (x−3)2=36(x-3)^2=36?

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How do you solve ${(x - 3)}^{2} = 36$ $(x-3)^2=36$ ?