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How do you solve x- 3 > 3 and -x + 1 < -2?

1 Answer

Vinícius Ferraz

Jul 11, 2015

$x \in] 6, \infty [$ $x \in ]6, \infty[$

Explanation:

$x > 3 + 3$ $x > 3 + 3$ and $1 + 2 < x$ $1 + 2 < x$

$x > 6 and x > 3$ $x > 6 and x > 3$

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