How do you solve $x^{3} - 5 x^{2} - 36 x + 180 = 0$ $x^3 − 5x^2 − 36x + 180 = 0$ ?

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Answer 1 · 2016-05-30T00:36:03

You can solve this one easily by factoring.

$x^{2} (x - 5) - 36 (x - 5) = 0$ $x^2(x - 5) - 36(x - 5) = 0$

$(x^{2} - 36) (x - 5) = 0$ $(x^2 - 36)(x - 5) = 0$

$x^{2} = 36 and x = 5$ $x^2 = 36 and x = 5$

$x = \pm 6 and 5$ $x = +-6 and 5$

Hopefully this helps!

How do you solve x3−5x2−36x+180=0x^3 − 5x^2 − 36x + 180 = 0?