How do you solve $x^{3} + 8 x^{2} = - 16 x$ $x^3+8x^2=-16x$ ?

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How do you solve $x^{3} + 8 x^{2} = - 16 x$ $x^3+8x^2=-16x$ ?

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Answer 1 · 2017-02-07T21:56:48

$x = 0 XX or XX x = - 4$ $x=0color(white)("XX")orcolor(white)("XX")x=-4$

Explanation:

If $x \neq 0$ $x!=0$ we can divide both sides by $x$ $x$
So
${: ("either",x=0,color(white)("XX")orcolor(white)("XX"),x^2+8x=-16), (,,,rarr x^2+8x+16=0), (,,,rarr (x+4)^2=0), (,,,rarr x=-4) :}$

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How do you solve $x^{3} + 8 x^{2} = - 16 x$ $x^3+8x^2=-16x$ ?

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How do you solve $x^{3} + 8 x^{2} = - 16 x$ $x^3+8x^2=-16x$ ?