How do you solve $x^3 - x^2 - 12x = 0$ ?

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Answer 1 · 2016-03-15T01:02:35

You can first factor out an x from each term to the left of the =.

$x(x^2 - x - 12) = 0$

Solve by factoring:

$x(x - 4)(x + 3) = 0$

$x = 0, 4 and -3$

Hopefully this helps.

How do you solve x^3 - x^2 - 12x = 0x^3 - x^2 - 12x = 0?