How do you solve $x + 3 x - 4 = 32$ $x+3x - 4= 32$ ?

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Answer 1 · 2016-02-10T14:13:16

x = 9

x + 3x - 4 = 32

add 4 to both sides : x + 3x - 4 + 4 = 32 + 4

so 4x = 36

divide both sides by 4

$( cancel(4) x)/cancel(4) = 36/4 rArr x = 9$

How do you solve x+3x - 4= 32x+3x−4=32x+3x - 4= 32?