How do you solve $x (3 x + 5) = 15 + 5 x$ $x(3x + 5) = 15 + 5x$ ?

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Answer 1 · 2016-09-19T01:28:10

$x = \pm \sqrt{5}$ $x = +-sqrt(5)$

$3 x^{2} + 5 x = 15 + 5 x$ $3x^2 + 5x = 15 + 5x$

$3 x^{2} - 15 = 0$ $3x^2 - 15 = 0$

$3 (x^{2} - 5) = 0$ $3(x^2 - 5) = 0$

$x = \pm \sqrt{5}$ $x = +-sqrt(5)$

Hopefully this helps!

How do you solve x(3x + 5) = 15 + 5xx(3x+5)=15+5xx(3x + 5) = 15 + 5x?