Science

Math

Humanities

... and beyond

Socratic Meta
Featured Answers

Topics

How do you solve ${(x + 4)}^{2} = 11$ $(x + 4)^2 = 11$ ?

1 Answer

Oct 29, 2015

$x = - 4 - \sqrt{11} XXX$ $x=-4-sqrt(11)color(white)("XXX")$ or $XXX x = - 4 + \sqrt{11}$ $color(white)("XXX")x=-4+sqrt(11)$

Explanation:

Given
$XXX {(x + 4)}^{2} = 11$ $color(white)("XXX")(x+4)^2=11$

then
$XXX x + 4 = \pm \sqrt{11}$ $color(white)("XXX")x+4 = +-sqrt(11)$
and
$XXX x = - 4 \pm \sqrt{11}$ $color(white)("XXX")x=-4+-sqrt(11)$

Related questions

See all questions in Comparing Methods for Solving Quadratics

Impact of this question

2108 views around the world

You can reuse this answer
Creative Commons License