How do you solve ( x - 4)^2 = 12?

1 Answer
Nallasivam V
Mar 31, 2016

x=7.464
x=0.536

Explanation:

Given -

(x-4)^2=12
x^2-8x+16=12
x^2-8x+16-12=0
x^2-8x+4=0
x=(-b+-sqrt(b^2-(4ac)))/(2a)
x=(8+-sqrt((-8)^2-(4 xx1 xx4)))/(2 xx 1)
x=(8+-sqrt(64-16))/2
x=(8+-sqrt(48))/2
x=(8+-6.928)/2
x=(8+6.928)/2=14.928/2=7.464
x=7.464
x=(8-6.928)/2=1.072/2=0.536
x=0.536

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