How do you solve (x-5)^2=4? Algebra Quadratic Equations and Functions Comparing Methods for Solving Quadratics 1 Answer Alan P. Jun 16, 2016 x in {3, 7} Explanation: (x-5)^2=4 rArr color(white)("XXX"){: ("either",(x-5)=2,color(white)("XX")"or"color(white)("XX"),(x-5)=-2), (,rarr x=7,,rarrx=3) :} Answer link Related questions What are the different methods for solving quadratic equations? What would be the best method to solve -3x^2+12x+1=0? How do you solve -4x^2+4x=9? What are the two numbers if the product of two consecutive integers is 72? Which method do you use to solve the quadratic equation 81x^2+1=0? How do you solve -4x^2+4000x=0? How do you solve for x in x^2-6x+4=0? How do you solve x^2-6x-16=0 by factoring? How do you solve by factoring and using the principle of zero products x^2 + 7x + 6 = 0? How do you solve x^2=2x? See all questions in Comparing Methods for Solving Quadratics Impact of this question 1100 views around the world You can reuse this answer Creative Commons License